Subject: [xsl] Building attributes using another template, context node? From: "Manos Batsis" <m.batsis@xxxxxxxx> Date: Thu, 25 Oct 2001 12:27:51 +0300 |
Hi folks, I would really appreciate some help on this one :-) Suppose I have the following: <html:table cellspacing="0" cellpadding="0" xed:nodeType="element" xmlns:xed="http://www.foo.org/foo/"> <html:tr> <html:td class="elemType"> <html:button class="shown"/> <html:p class="elemNameTextArea">xsl:stylesheet</html:p> </html:td> <html:td class="childHolder"> <html:div class="hide"> <html:table cellspacing="0" cellpadding="0" xed:nodeType="attribute"> <html:tr> <html:td class="attrType"> <html:button class="hidden"/> <html:p class="elemAttrTextArea">version</html:p> </html:td> <html:td> <html:p class="xedValue" xed:areaType="attrValue">1.0</html:p> </html:td> </html:tr> </html:table> </html:div> </html:td> </html:tr> </html:table> I have a template that matches the outer table with the xed:nodeType="element" attribute-value pair. I use it to output an element from the html:p in it's first TD. Now, the problem. I am trying to construct the attribute of that element, using the inner table (the one with the xed:nodeType="attribute"). My template for the first table is: <xsl:template match="table[@xed:nodeType='element']"> <xsl:element name="{tr/td[@class='elemType']/p/text()}" xml:space="preserve"> <xsl:apply-templates select="tr/td[@class='childholder']/div/table" mode="scrapattrs"/> <xsl:apply-templates/> </xsl:element> </xsl:template> This is a really messed up version of the second template... <xsl:template name="scrapattrs" mode="scrapattrs" match="table[@xed:nodeType='attribute']"> <xsl:attribute name="{tr/td[@class='attrType']/p/text()}"> <xsl:value-of select="tr/td/p[@areaType='attrValue']/text()"/> </xsl:attribute> </xsl:template> Can you point me to modifications needed to build the element and it's properties? Thank you very much for your time. Kindest regards, Manos XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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