RE: [xsl] sorting problem

Subject: RE: [xsl] sorting problem
From: DPawson@xxxxxxxxxxx
Date: Thu, 25 Oct 2001 14:38:52 +0100


> I don't understand the question.
> 
> 
> After this:
> 
>     <xsl:for-each select="r">
> 
> you are only hgoing to get each r element once.

There are 12800 r elements.

> 
> so what is "a" here and why does it appear twice?

is the contents of the <termX> element.

I eventually resolved it with
 <xsl:sort select="m655/*[last()]"/>
 
which I was quite surprised to find worked!

The functionality is to sort by bubbling up lower numbers,
giving a level sort which might be depicted as
  term10 term4 term3
  term 9 term8 term7
  term 3 term 2

This would be the case for successive part records of

<r>
   ..
  <m655>
    <tag>
    <term1>
     ...
    <term10>

<r>
   ..
  <m655>
    <tag>
    ...
    <term3>
    <term4>
 
etc.


I.e. it sorted on the last one, irrespective of what 'number'
was present for X in termX.



I'm nearly there, just need to find out how to do it for
lower level groupings.


Regards DaveP

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