[xsl] position of a child node

Subject: [xsl] position of a child node
From: "Carmelo Montanez" <carmelo@xxxxxxxx>
Date: Thu, 15 Nov 2001 12:32:25 -0500
Hi all:

I hope I can get an answer to these questions:

    Suppose I have the following portion of an xml file

<testcase>
  <child1>first text</child1>
  <child2>
    <child21>
        some text here
    </child21>
  </child2>
</testcase>

and my context node is "testcase" and I want to find out the position of the
descendant text node "some text here", whats the easiest way to do that?, I
been
playing with "<xsl:number>" and "count()" with no success.

I really will want to know that position without having to change my context
node, which leads me to another question ....., if I do traverse the tree
down
to where the text is, Is there a way to change the context node  back to
"testcase"?

Greetings,
Carmelo Montanez
----- Original Message -----
From: "Chen, Gin" <Gin_Chen@xxxxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Thursday, November 15, 2001 12:09 PM
Subject: RE: [xsl] OK, stupid Q time


> Okay... everyone seems to agree that it is <BR/>.
> My question then is.. how do you get that BR to be displayed when
> translating the XML with a XSL?
> For example:
> My XML has this
>       <paragraph>This is my first <BR/> page</paragraph>
> And my XSL has this
> <font color="red"><xsl:value-of select="paragraph"/></font>
> But it seems to ignore the <BR/>. I get output like:
> This is my first  page
> I set the output to html using:
> <xsl:output method="html"/>
> -Tim
>
> -----Original Message-----
> From: David Carlisle [mailto:davidc@xxxxxxxxx]
> Sent: Thursday, November 15, 2001 11:47 AM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] OK, stupid Q time
>
>
>
> It's XML: empty BR is <BR/>
>
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