RE: [xsl] Is there a way in xsl to point to a node if only a part of its name is known?

[Joshua.Kuswadi@xxxxxxxxxxxxxxxxxxxx]

Michael wrote: 
> Is there a way in xsl to point to a node if only a part of its name is
> known?

>From what I know, there is no wildcard to partially match node names. The only thing close is select="*" which will select all elements. You could try using the XPath name() or local-name() function to return the node name as a string and then test if for what ever you need.

> Sample xml 1:
> <node1>
>   <node2>
>     <node3>
>       <tableName1.field1>content ...</tableName1.field1>
>       <tableName1.field2>content ...</tableName1.field2>
>       <tableName1.field3>content ...</tableName1.field3>
>     </node3>
>   </node2>
> </node1>

eg a template for the above XML sample (Note: This is untested, no guarantees ;-)
<xsl:template match="node3">
 <xsl:for-each select="*">
  <!-- Should select the fieldname after the dot, '.', in the element name
  <xsl:variable name="fieldname" select="substring-after(local-name(), '.')" />
  <xsl:if test="$fieldname = 'foo'">
   <!-- Do stuff when element has 'foo' as the fieldname
  </xsl:if>
 </xsl:for-each>
</xsl:template>

HTH,
Joshua

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