Subject: Re: [xsl] newbie question... From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Thu, 29 Nov 2001 11:38:29 +0000 |
Hi Terje, > I got a simple table where I receive 4 variables from the xsql > query:PNS (nom. size), POD (dia.(mm)), PWTH (Wall th.(mm)) and PSCH > (Schedule). The result is presented on a web-page, but because we > also want to print it out, we are not able to present more than 22 > records in each table. How do I tell the XSL to start printing a new > table when it has reached 22 records? You need to group using the position() of the ROW. You want the 1st, 23rd, 45th etc. ROW elements to generate a new table, so apply templates only to those ROW elements: <xsl:apply-templates select="ROW[position() mod 22 = 1]" /> and have a template that matches ROW elements and creates the table element. For the rows, it needs to look at that ROW element and its following 22 siblings. I'd store these in a variable since you're going to use them again and again to create each row. Then create the cells in each row by iterating over $rows: <xsl:template match="ROW"> <table class="no" style="width:170mm;padding:1pt;" cellspacing="0" border="1"> <xsl:variable name="rows" select=". | following-sibling::ROW[position() < 22]" /> <tr> <td class="b">Nom. Size(in)</td> <xsl:for-each select="$rows"> <td class="lb"><xsl:value-of select="PNS" /></td> </xsl:for-each> </tr> <tr> <td class="t">dia.(mm)</td> <xsl:for-each select="$rows"> <td class="lt"><xsl:value-of select="POD" /></td> </xsl:for-each> </tr> <tr> <td class="t">Wall th.(mm)</td> <xsl:for-each select="$rows"> <td class="lt"><xsl:value-of select="PWTH" /></td> </xsl:for-each> </tr> <tr> <td class="t">Schedule</td> <xsl:for-each select="$rows"> <td class="lt"><xsl:value-of select="PSCH" /> </td> </xsl:for-each> </tr> </table> </xsl:template> I hope that helps, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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