Subject: Re: [xsl] Default template match From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Mon, 3 Dec 2001 13:28:14 +0000 |
Hi Costantino, > Therefore, how can I refer to the specific customer (from the > "metadata" file), when I am applying other templates? Passing it down as a parameter is the only way of doing it. By the way, you could make your stylesheet more readable and efficient by changing the way that you access the information in the metadata.xml document so that you use a key instead. Create a key that indexes each doc element by its label and lang attributes, as follows: <xsl:key name="docs" match="doc" use="concat(@lang, '::', @label)" /> Then change your code as follows: <!-- iterate over each doc from metadata.xml --> <xsl:for-each select="document($metadata)/data/doc"> <!-- assign the doc to the $doc-ref variable --> <xsl:variable name="doc-ref" select="." /> <doc> <!-- create the metadata element for the doc --> <metadata><xsl:copy-of select="*" /></metadata> <!-- change context to templates.xml --> <xsl:for-each select="document($templates)"> <!-- use the key to get hold of the doc --> <xsl:variable name="doc" select="key('docs', concat($doc-ref/label, '::', $doc-ref/customer/language))" /> <!-- create the object and content elements for the doc --> <object> <xsl:apply-templates select="$doc/object"> <xsl:with-param name="doc-ref" select="$doc-ref" /> </xsl:apply-templates> </object> <content> <xsl:apply-templates select="$doc/content"> <xsl:with-param name="doc-ref" select="$doc-ref" /> </xsl:apply-templates> </content> </xsl:for-each> </doc> </xsl:for-each> Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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