[xsl] Re: adding unique values to a drop-down list

["E100 SFYang" <SFYang@xxxxxxxxxxxxx>]

Hi,Katie

To get a unique set of Broker and Id, using key and muenchian method is
suggested
as follows:

  <xsl:key name="nameid" match="Broker" use="concat(Name,'-',Id)" /> 

then define variable which defines the unique set of Broker node with
unique Name and Id

<xsl:variable name="nameid" select="Loans/Loan/BrokerSet/Broker[count(.
|key('nameid',concat(Name,'-',Id))[1]) = 1]" /> 

**xsl list **

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
	<xsl:output method="html"/>
	<xsl:key name="nameid" match="Broker"
use="concat(Name,'-',Id)"/>
	<xsl:variable name="nameid" 
		select="Loans/Loan/BrokerSet/Broker[count(.
|key('nameid',concat(Name,'-',Id))[1]) = 1]" /> 
	<xsl:template match="/">
	<form action="">
	<select name="FOO">
<!--  filter out the empty Id  using string(Id) -->
	<xsl:for-each select="$nameid[string(Id)]">
	<xsl:sort select="Name" />
	<xsl:sort select="Id"/>
	<option value="{Id}">
		<xsl:value-of select="Name"/> - <xsl:value-of
select="Id"/>
	</option>
</xsl:for-each>
		</select>
	</form>
	</xsl:template>
</xsl:stylesheet>

cheers,

sfyang@xxxxxxxxxxxxx

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