Subject: [xsl] Re: adding unique values to a drop-down list From: "E100 SFYang" <SFYang@xxxxxxxxxxxxx> Date: Wed, 5 Dec 2001 11:53:52 +0800 |
Hi,Katie To get a unique set of Broker and Id, using key and muenchian method is suggested as follows: <xsl:key name="nameid" match="Broker" use="concat(Name,'-',Id)" /> then define variable which defines the unique set of Broker node with unique Name and Id <xsl:variable name="nameid" select="Loans/Loan/BrokerSet/Broker[count(. |key('nameid',concat(Name,'-',Id))[1]) = 1]" /> **xsl list ** <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html"/> <xsl:key name="nameid" match="Broker" use="concat(Name,'-',Id)"/> <xsl:variable name="nameid" select="Loans/Loan/BrokerSet/Broker[count(. |key('nameid',concat(Name,'-',Id))[1]) = 1]" /> <xsl:template match="/"> <form action=""> <select name="FOO"> <!-- filter out the empty Id using string(Id) --> <xsl:for-each select="$nameid[string(Id)]"> <xsl:sort select="Name" /> <xsl:sort select="Id"/> <option value="{Id}"> <xsl:value-of select="Name"/> - <xsl:value-of select="Id"/> </option> </xsl:for-each> </select> </form> </xsl:template> </xsl:stylesheet> cheers, sfyang@xxxxxxxxxxxxx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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