[xsl] A little question...

Subject: [xsl] A little question...
From: Alessio Mazzieri <mazzieri@xxxxxxxxxxx>
Date: Wed, 05 Dec 2001 16:49:29 +0100
Hi to all,
I need to know the filename of the xml being processed by the xslt stylesheet, something like this...


The XML doc: (test.xml)
?xml version="1.0"?>
<?cocoon-process type="xslt"?>
<?xml-stylesheet href="filename.xsl" type="text/xsl"?>
.
.
.

The XSLT stylesheet (filename.xsl)
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0">
<xsl:template match="/">
<xsl:variable name="self">
<?SOME_INSTRUCTION_TO_OBTAIN_XML_FILENAME?>
</xsl:variable>
The original XML doc: <xsl:value-of select="$self"/>
</xsl:template>
</xsl:stylesheet>


The desidered output:
The original XML doc: test.xml

Some ideas?
Thanks.


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