Subject: Re: [xsl] transformNode() returning xsl code NOT desired html From: Francis Norton <francis@xxxxxxxxxxx> Date: Thu, 06 Dec 2001 12:09:30 +0000 |
In my ASP call to transformNode() i get the actual XSL code. i have been developing this thing for about a month and it has worked fine on my dev machine. the instant i make it live on the server transformNode() stops working and returns the code that is supposed to format my raw xml. anybody know what im doing wrong?? thanks fer yer help...
jibran...
*************ASP SNIPIT********************** var xml=Server.CreateObject("MSXML.DOMDocument"); var xsl=Server.CreateObject("MSXML.DOMDocument"); //populate both with data. Write.Response(xml.transformNode(xsl));
(i am able to see this when i view source on the browser) **********WRITE.RESPONSE OUTPUTS THE FOLLOWING******* <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="text" /> <xsl:template match="/"> //of course i do alot more stuff in here, but i didn't want to bloat the email.... </xsl:template> </xsl:stylesheet>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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