RE: [xsl] XSL Template Match using z:row attributes

Thanks Tom.  I learned a bit more already.  However, I still can't get
it to work.  I understand recursion, but maybe not in XSL.

Here's my modified xsl:

<?xml version='1.0'?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; 
				version="1.0">

<xsl:template match="/">
	<HTML>
	<BODY topmargin="0" leftmargin="0">
	<xsl:apply-templates select="/xml/rs:data/z:row"/>
	</BODY>
	</HTML>
</xsl:template>

<xsl:template match="../z:row[(@LEVEL=current()/@LEVEL + 1) and (@PARENTCATEGORYID
= current()/@CATEGORYID)">
	<div class="clsItem">
		<span class="clsSpace" type="img"><span class="clsCollapse">+</span></span><span
class="clsLabel" type="label">
			<xsl:attribute name="id"><xsl:value-of select="@CATEGORYID"/></xsl:attribute>
			<xsl:attribute name="parentid"><xsl:value-of
select="@PARENTCATEGORYID"/></xsl:attribute>
			<xsl:attribute name="title"><xsl:value-of select="@CATEGORYNAME"/></xsl:attribute>
			<xsl:value-of select="@CATEGORYNAME"/>
		</span>
	  <div>
		<xsl:apply-templates select="../z:row[(@LEVEL=current()/@LEVEL
+ 1) and (@PARENTCATEGORYID = current()/@CATEGORYID)"/>
	  </div>
	</div>
</xsl:template>

</xsl:stylesheet> 


Here's the input (I trimed it down a bit):

<?xml-stylesheet type="text/xsl" href="CategoryTree.xsl" ?>
<xml xmlns:s='uuid:BDC6E3F0-6DA3-11d1-A2A3-00AA00C14882'
	xmlns:dt='uuid:C2F41010-65B3-11d1-A29F-00AA00C14882'
	xmlns:rs='urn:schemas-microsoft-com:rowset'
	xmlns:z='#RowsetSchema'>

<rs:data>
	<z:row LEVEL='1' CATEGORYNAME='Product 1' CATEGORYID='1' PARENTCATEGORYID='0'
CHILDSORTORDER='10'/>
	<z:row LEVEL='2' CATEGORYNAME='Department A' CATEGORYID='2' PARENTCATEGORYID='1'
CHILDSORTORDER='20'/>
	<z:row LEVEL='2' CATEGORYNAME='Department B' CATEGORYID='3' PARENTCATEGORYID='1'
CHILDSORTORDER='30'/>
	<z:row LEVEL='3' CATEGORYNAME='Prospect' CATEGORYID='5' PARENTCATEGORYID='4'
CHILDSORTORDER='50'/>
	<z:row LEVEL='4' CATEGORYNAME='Appointment' CATEGORYID='49' PARENTCATEGORYID='5'
CHILDSORTORDER='51'/>
	<z:row LEVEL='4' CATEGORYNAME='Follow Up' CATEGORYID='50' PARENTCATEGORYID='5'
CHILDSORTORDER='52'/>
	<z:row LEVEL='4' CATEGORYNAME='Invitation' CATEGORYID='51' PARENTCATEGORYID='5'
CHILDSORTORDER='53'/>
</rs:data>
</xml>

The output I get now is:

+

Just one + sign....?  I assume that's the text() portion....  I greatly
apprecaite all you help.  Thank you,

Michael =:-)




---- TSchutzerWeissmann@xxxxxxxxxxxxxxxx wrote:
> Michael wrote:
> 
> >What I am getting is this:
> >
> >+ Product 1 
> >+ Product 2 
> >
> >It appears that I get the LEVEL='1', but not the remaining.  I wonder
> >if there's a way around 'hard coding' the LEVEL's in case I have more
> >than 4 or 5..??  I know it would be easier if my XML was is a different
> >format, but I'm forced to use the MS ADO export format.  Thank you,
> in
> >advance, for your help.
> 
> Hi Michael,
> 
> the problem here is something like this: your input isn't nested, and
> you
> want to nest it according to a LEVEL attribute.
> There are three problems with your approach.
> 
> 1. You're doing the same thing in 5 different templates. Try recursion
> instead, then you don't need to worry about how many levels you have.
> 
> 
> 2. The location paths in your <xsl:apply-templates>.
>  You use paths fine when you select attributes, so I assume you're
> using the
> full path (xml/rs:data/z:row) here because you want to get up out of
> your
> current context (a qualified z:row).
> To make your paths work, either use /xml/rs:data/z:row - the "/" will
> get
> you back to the document node, or use ../z:row[@LEVEL=2]- in longhand
> that's
> parent::node()/z:row[@LEVEL=2]. It's just like file directories.
> 
> BUT: it still won't work...
> 3. Matching children with parents.
> To get the nesting right you have to put the right children with the
> right
> parents. In your input you have CATEGORYID and PARENTCATEGORYID. A
> revised
> path, still using your approach would be
> 	"../z:row[(@LEVEL=2) and (@PARENTCATEGORYID =
> current()/@CATEGORYID)"
> or even 
> 	"../z:row[(@LEVEL=current()/@LEVEL + 1) and (@PARENTCATEGORYID
> =
> current()/@CATEGORYID)"
> You need current() not . because inside a predicate expression . is
> the node
> being evaluated, not the node matched by the current template.
> 
> Only recurse...
> Tom S-W
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
> 

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