Subject: [xsl] How do I compare all similar type nodes? From: "Ahmad J Reeves" <ahmad@xxxxxxxxxxxxxx> Date: Mon, 17 Dec 2001 23:04:36 -0000 |
Hi, I am trying to remove duplicate copies of context nodes from a sorted list. My xml doc looks like this:- <LOG> <DIRECT> <COMMUNICATION_TYPE> PAGETELL </COMMUNICATION_TYPE> <Invoc_serial> 27 </Invoc_serial> <Serial> 3087908 </Serial> <USAGE> TELL </USAGE> <MESSAGE_TYPE> EMOTE </MESSAGE_TYPE> <CHARACTER_ID> 44639 </CHARACTER_ID> <CHARACTER_STATUS> 3 </CHARACTER_STATUS> <LOCATION_ID> 45040 </LOCATION_ID> <TARGET_CHARACTER_ID> 2346456 </TARGET_CHARACTER_ID> <TARGET_CHARACTER_STATUS> 6 </TARGET_CHARACTER_STATUS> <TARGET_CHARACTER_LOCATION_ID> 23222 </TARGET_CHARACTER_LOCATION_ID> <MESSAGE>hello</MESSAGE> <TIME> 'Mon, 26 Nov 2001 15:40:29 +0000' </TIME> </DIRECT> *then a few hundred more like that* </LOG> My revised xml stylesheet as is looks like this:-(thanks chris) <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="html"/> <xsl:template match ="/"> <html> <body> <xsl:for-each select="LOG/DIRECT/TARGET_CHARACTER_ID[. != preceding-sibling::TARGET_CHARACTER_ID]"> <xsl:sort select="." data-type="number" order="ascending" /> <xsl:value-of select="position()" /><xsl:value-of select="." /> </xsl:for-each> </body> </html> </xsl:template> </xsl:stylesheet> The output still includes duplicates from the sorted list. I think preceding sibling doesnt compare all target_character_id nodes against eachother, how can I do this to prevent prinitng out duplicates? Cheers Ahmad 1. 23220 2. 23470 3. 23470 4. 23470 5. 23470 6. 23470 7. 23470 8. 83470 9. 212120 10. 223232 11. 231212 12. 2346456 13. 27675340 Cheers Ahmad. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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