Subject: [xsl] De-flattening an XML tree From: Benjamin Johnston <s355171@xxxxxxxxxxxxxxxxx> Date: Wed, 9 Jan 2002 11:24:33 +1000 (GMT+1000) |
Hi, I'm kind of stuck on ideas for how I might de-flatten a tree. It seems that I can't get the position of the next sibling with some property and I end up going around in circles with checking siblings because filter predicates seem to only work with one node at a time. If I've got something like; <recordset> <record/> <data/> <data/> <record/> <data/> <record/> <data/> <data/> <data/> </recordset> ie. we've got a record tag, followed by it's "children". Is there any way of transforming this to: <recordset> <record> <data/> <data/> </record> <record> <data/> </record> <record> <data/> <data/> <data/> </record> </recordset> Any suggestions, ideas or strategies? Thanks a lot! -Benjamin Johnston s355171@xxxxxxxxxxxxxxxxx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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