Subject: Re: [xsl] Get an element with max. number of certain children element From: Xiaocun Xu <xiaocunxu@xxxxxxxxx> Date: Fri, 18 Jan 2002 12:04:45 -0800 (PST) |
Hi, Jeni: Yeah, you are right, I meant "shorter" :) Looks like shorter solution is less efficient; while more efficient solution is longer. I eventually went with the recusrive template solution you have suggested to accomplish what I needed. Much thanks, Xiaocun > > I am aware of the solutions (via recursion > or temp node-set) > > that uses $maxAttachment as a number > (count(Attachment)), but is > > there a more elegent solution that does not > require > > processor-dependent extensions? > > If by 'more elegant', you mean shorter, then I think > that what you're > after is a way of finding the LineItem elements that > contain the > $maxAttachment number of Attachment elements. You > could do this with: > > <xsl:for-each select="LineItem[count(Attachment) = > $maxAttachment][1] > /Attachment"> > <xsl:text>,Name,URL,Description</xsl:text> > </xsl:for-each> > > [Note that if there's more than one LineItem with > the same (maximum) > number of Attachment children, then you'll get the > first one in > document order.] > > It's short, but it is not very efficient - not only > do you have to go > through all the LineItem elements in order to work > out what the > $maxAttachment is, you have to go through them all > again, doing > exactly the same calculation on them, to work out > whether they're the > one with the maximum number of attachments. But you > might not care > about performance, I guess... > > Cheers, > > Jeni > > --- > Jeni Tennison > http://www.jenitennison.com/ > __________________________________________________ Do You Yahoo!? Send FREE video emails in Yahoo! Mail! http://promo.yahoo.com/videomail/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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