Subject: [xsl] exclude-result-prefixes and xsl:copy issue From: Joerg Pietschmann <joerg.pietschmann@xxxxxx> Date: Fri, 01 Feb 2002 14:07:14 +0100 |
Hi, there is a note about exclude-result-prefixes in the XSLT spec: > NOTE: ... specifying the prefix > in the [xsl:]exclude-result-prefixes attribute will avoid > superfluous namespace declarations in the result tree. (Quote intentional snipped) I have a sort of template framework to get HTML snippets into various final layout (example drastically simplified): <t:template xmlns:t="my.namespace"> <t:content> <p>some content</p> </t::content> </t:template> <xsl:stylesheet xmlns:xsl="..." xmlns:t="my.namespace" exclude-result-prefixes="t"> <xsl:template match="t:template"> <html> <body> <xsl:call-template name="navigation"/> <xsl:apply-templates select="t:content/*"/> </body> <html> </xsl:template> <!-- the copy template --> <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="node()|@*"> </xsl:copy> </xsl:template> </xsl:stylesheet> The xsl:copy copies the t namespace node, as explicitely mentioned in the spec, which in turn is serialized into the result, also more or less explicitely mentioned in the XSLT 2.0 draft (not so clear in 1.0), this yields <html> <body> <p xmlns:t="my.namespace">some content</p> </body> </html> >From my point of view this is not in the spirit of the note quoted at the beginning. Is this an unintended consequence of how the 1.0 standard was written or are there cases where this behaviour is useful or necessary? Will it break existing style sheets or will it unnecessarily complicate implementations if unecessary namespaces would also be excluded from copied nodes? Well, meanwhile i helped myself by replacing xsl:copy with <xsl:element name="{name()}"> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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