Subject: Re: [xsl] Dynamic XPATH problem From: Joerg Heinicke <joerg.heinicke@xxxxxx> Date: Tue, 05 Mar 2002 14:13:23 +0100 |
Hi
I have a piece of code that goes like this:
<xsl:for-each select="LIBRARY/*/TRAVELINFO/*"> <TR valign="center"> <TD> <xsl:value-of select="NAME" /> </TD> </TR> </xsl:for-each>
and I want to swap-out the TRAVELINFO node for the content of:
//LIBRARY/CURRENTNODE
So perhaps something like this??
<xsl:for-each select="LIBRARY/*/(//LIBRARY/CURRENTNODE)/*"> <TR valign="center"> <TD> <xsl:value-of select="NAME" /> </TD> </TR> </xsl:for-each>
But cant get it to work.
Thanks
Lea
System Development VIRBUS AG Fon +49(0)341-979-7411 Fax +49(0)341-979-7409 joerg.heinicke@xxxxxxxxx www.virbus.de
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