Subject: Re: [xsl] getting associated file name for element From: "Gennady Loskutov" <g_loskutov@xxxxxxxxxxxxx> Date: Thu, 7 Mar 2002 14:16:26 +0100 |
> How can I grab the value of @href as each question is evaluated? Matthew, To determine URL of the file, where the current node is located, you can use generate-id() function. The root node for your current node must have the same id generated by generate-id() function as the one generated for one of the root nodes of the documents compiled together via document() function. Therefore, you need to define a variable for the root node of the current node: <xsl:variable name="doc" select="generate-id(/)" /> and get the URL by: <xsl:value-of select="$all-questions//quiz[generate-id(document(@href)) = $doc]/@href" /> Also, I suggest that you avoid using // operator if you know the path to quiz elements beforehand - for example, selecting "$all-questions/myquiz/quiz" is faster than "$all-questions//quiz" if $all-questions contains other children than myquiz. Regards, Gennady XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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