Subject: Re: [xsl] problems with transforming xml with xsl! sample inside From: Joerg Heinicke <joerg.heinicke@xxxxxx> Date: Thu, 14 Mar 2002 14:33:14 +0100 |
<xsl:template match="paragraph"> <xsl:apply-templates/> </xsl:template>
<xsl:template match="linkRef"> <a href="id(@id)/@value"><xsl:value-of select="id(@id)/@name"/></a> </xsl:template>
i have the following xml:
<doc> <links> <link id="lr1" name="xyz" value="xyz.com" /> <link id="lr2" name="abc" value="abc.com" /> </links> <paragraphs> <paragraph title="foo"> some text here, some text here <linkRef id="lr1"/> another text, another text <linkRef id="lr2"/> and even more text. </paragraph> </paragraphs> </doc>
the result should look like this:
foo some text here, some text here xyz.com another text, another text abc.com and even more text.
the goal is to transform this xml with a xsl. now the problem is, that i'm
not able to replace the <linkRef> with the specfied link. i tried to do it
within xsl and tried to do it with dom in asp. i don't know how i can
realize that. anyone knows a solution? thanks for any help.
i heard something about transorming it twice.. but i dunno how to do it.
J.M.K
Software Developer
Unit.Net AG Thurgauerstrasse 54 CH - 8050 Zurich
Email: jan.krattiger@xxxxxxxx Web: http://unit.net
System Development VIRBUS AG Fon +49(0)341-979-7411 Fax +49(0)341-979-7409 joerg.heinicke@xxxxxxxxx www.virbus.de
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