RE: [xsl] adding 2 formatted numbers?

[Jeff Beadle <Jbeadle@xxxxxxxx>]

this works...

<xsl:template match="/">
  <xsl:variable name="numbers">
    <xsl:for-each select="//node1/text() | //node2/text()">
	<n><xsl:value-of select="translate(.,',.','')"/></n>
    </xsl:for-each>
  </xsl:variable>
  <xsl:value-of select="sum(msxsl:node-set($numbers)//n)"/>
</xsl:template>

I'm sure others will post something more effecient, but like I said ... this
works.

Keep in mind that the format of the currency node content must be the same,
the segments be of the same type.

-Jeff

-----Original Message-----
From: L Rutker [mailto:lrutker@xxxxxxxxxxx]
Sent: Thursday, March 14, 2002 2:55 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] adding 2 formatted numbers?


Hi,
I have the following nodes in my xml:
<node1>123,456,789.01</node1>
<node2>222,222,222.54</node2>

In my xsl I have to add the value of the 2 of them. Since my numbers are 
formatted I cant do it.
How can I "unformat" my numbers and add them together?

Note: depending on the users currency formatting preferences I might get the

number in the following format:
<node1>123.456.789,01</node1>
<node2>222.222.222,54</node2>
I also have now way of knowing how many commas there are per node (the 
length varies)

Thanks
Lou

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