Subject: Re: [xsl] fileoutput From: Robert Koberg <rob@xxxxxxxxxx> Date: Mon, 18 Mar 2002 10:57:09 -0800 |
<xsl:apply-templates select="$schools/schools/school"> (and do your redirect:write in the school template match)
hi here is a problem i have :
i have an xml file schools.xml --file schools.xml --- <Schools> <school>cal</school> <school>london</school> <school>delhi</school> </schools>
--------------------------------------
my objective is to output each of the school names is a a different file called 'schoolname'-school.txt ( example delhi-school.txt)
and xsl file goes..
<?xml version="1.0"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xalan="http://xml.apache.org/xslt" xmlns:redirect="org.apache.xalan.xslt.extensions.Redirect" extension-element-prefixes="redirect" version="1.0"> <xsl:variable name = "schools" select ="document('schools.xml')"/> <xsl:template match="/"> <xsl:for-each select="$schools"> <xsl:variable name="sc" select="."/> <xsl:variable name="file" select="concat($sc,'-school','.txt')"/>
<redirect:write select="$file">
<!--
i want to output each time to a file called schoolname-school.txt (example delhi-school.txt)
-->
<xsl:value-of select="$sc"/>
</redirect:write>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
and there is another XML file against which i run this xsl.
The above code doesnt work!! obviously because of some problem which i am unable to understand. My questions:
1.can someone please tell me where i am going wrong ?? 2.Id i have a secondary document imported to my XSL file, can i get to their children by expression $DocumentName/child?? laura
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