[xsl] parent and ..

Subject: [xsl] parent and ..
From: Matts Isuls <matts.isuls@xxxxxxxxxxx>
Date: Tue, 19 Mar 2002 11:03:43 +0200
Hi list

How do i get the attribute of a nodes parent? If there are many nodes at the
same leve as the parent i get the first parents attribute. 

<?xml version="1.0"?>
<row>
  <cell pos="1">
    <data>d1</data>
  </cell> 
  <cell pos="2">
    <data>d2</data>
  </cell> 
  <cell pos="3">
    <data>d3</data>
  </cell> 
</row> 

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="html" version="1.0" encoding="ISO-8859-1" indent="yes"
omit-xml-declaration="no" standalone="yes"/>
<xsl:template match="/">
  <xsl:for-each select="row/cell">
    <xsl:value-of select="parent::*/cell/@pos"/>
  </xsl:for-each>
</xsl:template>
</xsl:stylesheet>


Output is '111'. Same result when select="parent::node()/cell/@pos" and
select="../cell/@pos". But how do i get '123'?


matts isuls

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