Subject: Re: [xsl] commandline parameters From: Joerg Heinicke <joerg.heinicke@xxxxxx> Date: Tue, 19 Mar 2002 11:12:06 +0100 |
<?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:value-of select="$commandparam"/> </xsl:template> </xsl:stylesheet>
My questions are:
1. If i want to read the parameter through -PARAM, is the above xsl correct?
2. what would be the command that runs in the commandline to pass on the parameter. would it be something like this..
java org.apache.xalan.xslt.Process -IN commandlineexp.xml
-XSL commandlineexp.xsl -OUT multi -PARAM commandparam commandparamvalue?
please let me know if i am wrong and in that case the correct syntax of the commandline statement and the xsl structure
laura
System Development VIRBUS AG Fon +49(0)341-979-7411 Fax +49(0)341-979-7409 joerg.heinicke@xxxxxxxxx www.virbus.de
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