Subject: [xsl] suppressing default template rules From: Aseef Jamaluddin <j_aseef@xxxxxxxxx> Date: Tue, 26 Mar 2002 02:28:20 -0800 (PST) |
Hi All, Please find below the xml and xsl files i am working on. What i am trying to do is print the firstname and secondname when the employee element is encountered. But now i am getting two sets of values printed. I assume that the second set is due to the built(default) in template rule for matching all text() nodes. If so what could be the way out. <?xml version="1.0" ?> <custdet> <employee> </employee> <firstname>first</firstname> <lastname>last</lastname> </custdet> <?xml version="1.0"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:template match="firstname"> <b> <xsl:value-of select="."/> </b> </xsl:template> <xsl:template match="lastname"> <i><b> <xsl:value-of select="."/> </b></i> </xsl:template> <xsl:template match="employee"> <xsl:apply-templates select="//firstname"/> <xsl:apply-templates select="//lastname"/> </xsl:template> </xsl:stylesheet> Thanks in advance aseef.j __________________________________________________ Do You Yahoo!? Yahoo! Movies - coverage of the 74th Academy Awards® http://movies.yahoo.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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