Subject: Re: [xsl] problem with xsl:number From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Wed, 27 Mar 2002 13:28:44 +0000 |
Hi Bryan, > <xsl:number> would give you the position of the element in the source > tree. Try giving a node value to the count attribute.. > <xsl:number count = "node you wana count"/> > thanks I'll try that. > althought I thought as a default it counted the current node? It does - more importantly, by default it counts at a level of 'single', so it gives you the position of the current node amongst other nodes of that type (and name) in the same parent. So if you have: <ol> <li>option 1</li> <li>option 2</li> ... </ol> and then match li elements and number them: <xsl:template match="li"> <xsl:number format="1. " /> <xsl:value-of select="." /> </xsl:template> then you get the correct numbering of 1 through to however many items there are in the list. You seem to want to number images across the *entire document* rather than within the parent element. If so, you should use the level attributeof xsl:number with a value of 'any', to say that you want to count the image amongst other images in the document rather than just its parent: <xsl:template match="image"> <xsl:number level="any" /> ... </xsl:template> Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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