Subject: [xsl] xsl:copy - change attributes and tag name From: "Matias Woloski" <woloski@xxxxxxxx> Date: Sat, 6 Apr 2002 16:43:18 -0300 |
Hi folks! I have this parent-child xml. <TreeData> <Indice IdIndice="1" Nombre="Omint Analisis" /> <Indice IdIndice="3" IdRef="1" Nombre="OMINT: Precios"/> <Indice IdIndice="4" IdRef="1" Nombre="210 / Omint"/> <Indice IdIndice="5" Nombre="Swiss Medical Analisis"/> <Indice IdIndice="6" IdRef="5" Nombre="Swiss Precios"/> <Indice IdIndice="7" IdRef="1" Nombre="310 / Omint"/> <Indice IdIndice="8" IdRef="7" Nombre="Cobertura" IdDoc="1"/> </TreeData> What I want to do is putting it into a hierarchical format, which I do with this xsl <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:template match="/"> <tree> <xsl:apply-templates select="TreeData/*[not(@IdRef)]"/> </tree> </xsl:template> <xsl:template match="*|@*"> <xsl:copy> <xsl:apply-templates select="//*[@IdRef = current()/@IdIndice]|@*"/> </xsl:copy> </xsl:template> </xsl:stylesheet> So I get <tree> <Indice IdIndice="1" Nombre="Omint Analisis"> <Indice IdIndice="3" IdRef="1" Nombre="OMINT: Precios Directos" /> <Indice IdIndice="4" IdRef="1" Nombre="210 / Omint" /> <Indice IdIndice="7" IdRef="1" Nombre="310 / Omint"> <Indice IdIndice="8" IdRef="7" Nombre="Cobertura" IdDoc="1" /> </Indice> </Indice> <Indice IdIndice="5" Nombre="Swiss Medical Analisis"> <Indice IdIndice="6" IdRef="5" Nombre="Swiss Precios" /> </Indice> </tree> Now I want 3 things: 1. instead of generate <Indice> tags I want to get <tree> tags. So I would get <tree> <tree ... /> <tree ..> <tree ..> </tree> </tree> 2. I want to change the "Nombre" attribute to "text" attribute So I would have <tree text="210/Omint" ...> 3. How do I add another attribute to each entry? <tree text="..." addedAttr="something"> thanks in advance! Matias XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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