Subject: Re: [xsl] sorting date prob From: "Joerg Heinicke" <joerg.heinicke@xxxxxx> Date: Thu, 11 Apr 2002 08:49:29 +0200 |
Hello Jarkko, you must bring the date to the format yyyymmdd. The best to do this is in the XML, because the date-formatting is a style-question, so it should be done in the stylesheet. If this is not possible, you can do it temporarily in the stylesheet too: <xsl:sort select="concat(substring(Time,7,2), substring(Time,4,2), substring(1,2))"/> Regards, Joerg > Hi! > > First things first. Thanks a lot Jeni for your advices about > selecting attribute for link value. > > Then another question: > I should sort the xml file ascending by the given date. > The xml syntax is like this: > > <Information> > <Time>06/04/02</Time> #format is dd/mm/yy > <Size>299</Size> > <Sender>Moilanen Jarkko</Sender> > <Subject id="00223322334342">Xalan</Subject> > </Information> > > <Information> > <Time>05/11/02</Time> > <Size>45</Size> > <Sender>Moilanen Jarkko</Sender> > <Subject id="00223322342334342">Atribuutit linkkeina</Subject> > </Information> > > If I try to sort them by xsl: > <xsl:sort order="ascending" select="Time" /> > > the result is not the correct one.Is there some solution to this, > or should the xml file be different concerning the syntax? XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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