Subject: [xsl] Copying attribute value From: "Uslu, Cihan Y (MED)" <Cihan.Uslu@xxxxxxxxxx> Date: Thu, 11 Apr 2002 18:07:56 -0500 |
Hi, I have an attribute whose deafult value is set to 'N' in DTD. ------------- optionalInfo (Y | N ) 'N' ------------ This is what I have in XML: --------------------------------- <a optionalInfo="Y"> <b/> <c/> </a> -------------------------------- I use this XSLT snippet: ------------------------------------------------------------- ....... <xsl:output method="xml" doctype-system="D:/docs/dtd/course_js.dtd"/> ........... <xsl:template match="*|@*|node() | text()"> <xsl:copy> <xsl:apply-templates select="*|@*|node() | text()"/> </xsl:copy> </xsl:template> .............. ------------------------------------------------------------ When I try to this element containing this attribute with it's value is set to 'Y', I still get 'N' after the transformation. I use the same DTD for both XML documents. What should I do to get the value in XML instead of the default value set in DTD? XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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