Subject: RE: [xsl] further question regarding the use of Muenchian Method From: "林 子芯" <minikittygo@xxxxxxxxxxx> Date: Tue, 16 Apr 2002 16:55:59 +0000 |
problem,From: "Michael Kay" <michael.h.kay@xxxxxxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Subject: RE: [xsl] further question regarding the use of Muenchian Method Date: Mon, 15 Apr 2002 20:01:37 +0100
Using multiple elements with different grouping keys shouldn't be a
because you can declare multiple <xsl:key> elements with the same name and you effectively get the union of all of them.
> -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of 林 子芯 > Sent: 15 April 2002 18:43 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] further question regarding the use of Muenchian Method
> i was wondering whether it is possible to group the content > given that they > belongs to a separate structure (i.e. > <booklist> > <adventure> > <author>author1</author> > <title>1</title> > <adventure> > <adventure> > <author>author2</author> > <title>2</title> > <adventure> > <adventure> > <author>author1</author> > <title>3</title> > <adventure> > <sci-fi> > <star-trek> > <author>author1</author> > <title>6</title> > </star-trek> > <star-trek> > <author>author4</author> > <title>9</title> > </star-trek> > </sci-fi> > </booklist> > > transform to > <booklist> > <books> > <author>author1</author> > <title>1</title> > <title>3</title> > <title>6</title> > </books> > <books> > <author>author2</author> > </title>2</title> > </books> > ...etc > > since there are two different 'forms' of author 'tags' (i am > sure there is > a better description) (i.e adventure/author and > sci-fi/star-trek) i could > not generate the appropiate key for mucheun method (well at > least i am not > certain how) but is there are a way to do so?
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