Subject: RE: [xsl] problem in using * as a default parameter in xsl:param From: "Michael Kay" <michael.h.kay@xxxxxxxxxxxx> Date: Mon, 29 Apr 2002 17:08:46 +0100 |
> > this is what i did: > > <xsl:param name="param1" select="*"/> > .... > <xsl:for-each select="elementName[childName=$param1]"> > <xsl:copy-of select="elementName"/> > </xsl:for-each> > ... > You're straying into dynamic XPath expressions here. If you don't want to use the xx:evaluate() extension, you can do: <xsl:param name="childElement" select="'*'"/> <xsl:for-each select="element[$childElement!='*][childName=$childElement] | element[$childElement='*']"> Michael Kay Software AG home: Michael.H.Kay@xxxxxxxxxxxx work: Michael.Kay@xxxxxxxxxxxxxx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] problem in using * as a defau, 林 子芯 | Thread | Re: [xsl] problem in using * as a d, Oleg Tkachenko |
Re: [xsl] A4, A3 or Letter layout-m, G. Ken Holman | Date | RE: [xsl] problem in using * as a d, TSchutzerWeissmann |
Month |