RE: [xsl] problem in using * as a default parameter in xsl:param

Subject: RE: [xsl] problem in using * as a default parameter in xsl:param
From: "Michael Kay" <michael.h.kay@xxxxxxxxxxxx>
Date: Mon, 29 Apr 2002 17:08:46 +0100
>
> this is what i did:
>
> <xsl:param name="param1" select="*"/>
> ....
> <xsl:for-each select="elementName[childName=$param1]">
> <xsl:copy-of select="elementName"/>
> </xsl:for-each>
> ...
>
You're straying into dynamic XPath expressions here. If you don't want to
use the xx:evaluate() extension, you can do:

<xsl:param name="childElement" select="'*'"/>

<xsl:for-each
   select="element[$childElement!='*][childName=$childElement] |
           element[$childElement='*']">

Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx


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