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Re: [xsl] Transformation in NetScape 6.2 Browser

Subject: Re: [xsl] Transformation in NetScape 6.2 Browser
From: "Roma Yankin" <polfin@xxxxxxxx>
Date: Thu, 9 May 2002 23:04:50 +0400
Hi Stuart!

Actually i've included some code that works both in NS and IE, but for some
reason it had been snipped. Or mysteriously disappeared somewhere. So here
is just the code again.

Styleshhets themselves are simply linked and thats the way the are applied
in Netscape. I don't know whether NS allows dynamic transforming of XSL
rules, so if anybody knows how it is done please post something on that
subject.
Code part

XML file:
-------------------------------------

<?xml-stylesheet type="text/xsl" href="xsl.xsl"?>
<sample>
  <hasattrib hasit="true">
    I have attribute
  </hasattrib>
  <ihave hasit="candy">
    I have attribute
  </ihave>
  <noattribute>
    Nothing here
  </noattribute>
  <mychildhave>
    <child hasit="toy"/>
  </mychildhave>
</sample>

XSL file
--------------------------------------------

<xsl:stylesheet
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
 version="1.0">
 <xsl:output method="html"/>
  <xsl:template match="/">
   <html>
    <body>
     <xsl:for-each select=".//*">
      <xsl:if test="@hasit">
        <b><xsl:value-of select="name()"/></b> have "hasit" attribute set to
        <b><xsl:value-of select="@hasit"/></b> <br/>
      </xsl:if>
     </xsl:for-each>
    </body>
   </html>
  </xsl:template>
</xsl:stylesheet>

Regards, Roman



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