Subject: [xsl] Calculating a sum of rounded numbers From: "Nik Krimm" <Nik.Krimm@xxxxxxxxxxxxxxx> Date: Thu, 9 May 2002 15:45:22 -0500 |
I am trying the following output from the XML below: [output] .21 .09 .2 sum: .5 [xml] <values> <value>.2123</value> <value>.0923</value> <value>.2012</value> </values> [xsl] <xsl:for-each select="value"> <xsl:value-of select="format-number((.),'.##')" /><br /> </xsl:for-each> sum: <xsl:value-of select="format-number(sum(//value),'.##)" /> Instead I'm getting the output [output] .21 .09 .2 sum: .51 i.e. a rounding error because the numbers are sumed first and then rounded, rather than rounded first and then summed. I tried <xsl:value-of select="format-number(sum(format-number(//measure),'##')" /> But get an error: Argument 1 must return a node-set. format-number(-->sum(format-number(//measure),'##')<--) Can anyone suggest a better way to approach this problem that is native xsl (i/e/ without extensions)? TIA nik XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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