Subject: [xsl] How to remove double elements????? From: ChivaBaba@xxxxxxx Date: Thu, 16 May 2002 12:16:02 EDT |
Hi, I have some pretty fussy code to copy some elements from an xml-file, sort them amd eliminate double elements: ++++++++++++++++++++++++++++++++++++++++++++++++++++++++ <!-- get for each computer in sw-file the corresponding computer in hw-file--> <xsl:variable name="computer"> <xsl:for-each select="tool"> <!--.... build the key of the current tool .........--> <xsl:variable name="key" select="concat(@name,'#',@version)"/> <!-........ change context for key lookup ..........--> <xsl:for-each select="$sw-file"> <xsl:variable name="release" select="key('releasekey',$key)"/> <xsl:for-each select="$release/computer"> <xsl:variable name="name_key" select="@name"/> <!--.......... change context for key lookup .......--> <xsl:for-each select="$hw-file"> <xsl:copy-of select="key('hw_key',$name_key)"/> </xsl:for-each> </xsl:for-each> </xsl:for-each> </xsl:for-each> </xsl:variable> <!--.............. get sorted computer-list .......--> <xsl:variable name="sorted_hw"> <xsl:for-each select="exsl:node-set($computer)/computer"> <xsl:sort data-type="text" lang="en" select="@function"/> <xsl:sort data-type="text" lang="en" select="@name"/> <xsl:copy-of select="."/> </xsl:for-each> </xsl:variable> <!--........... remove double elements .............--> <xsl:variable name="hw"> <xsl:for-each select="exsl:node-set($sorted_hw)/computer"> <xsl:if test="preceding-sibling::computer[1]/@name != @name"> <xsl:copy-of select="."/> </xsl:if> </xsl:for-each> </xsl:variable> ++++++++++++++++++++++++++++++++++++++++++++++++++++++++ 1.) Is there an elegant possibility to remove double elements??? By using my version the first element gets lost!! 2.) Is it possible to get these functionaltities with LESS code (especially with LESS variables)?????? Many thanks in advance!!! Cheers, Stefan XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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