Subject: Re: [xsl] Maybe newbie... From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Fri, 17 May 2002 15:03:23 +0100 |
Hi Antonio, > I think that using two nested for-each is quite dirty in my case, as > a very similar effect could be achieved with a <xsl:for-each > select="alarm/problemtype">. > > However, when using that one, position() is not 1, 2, 1, 2 but 1, 2, > 3, 4, so the third line does not show the dates, where it should. > > I know I can substitute position by something else, but... what? You could test whether the particular problemtype element has a preceding sibling problemtype element; if it doesn't, then it's the first within the particular alarm element: <xsl:for-each select="alarm/problemtype"> <tr> <xsl:choose> <xsl:when test="preceding-sibling::problemtype"> <td></td><td></td> </xsl:when> <xsl:otherwise> <td><xsl:value-of select="../@start" /></td> <td><xsl:value-of select="../@end" /></td> </xsl:otherwise> </xsl:choose> <td><xsl:value-of select="@qty" /></td> <td><xsl:value-of select="@type" /></td> </tr> </xsl:for-each> It doesn't save you much though; might even make the transformation marginally slower (it's easier to check the position of the current node than it is to check the preceding sibling of the current node, I think). Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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