Subject: Re: [xsl] Generating a list of items NOT present in source XML From: David Carlisle <davidc@xxxxxxxxx> Date: Fri, 17 May 2002 18:17:28 +0100 |
It depends a bit what your missing nodes are, if it's numbers then the stylesheet has a chance, if the thing is a list of family birthdays and I've forgotten one (not uncommon:-) then the stylesheet probably won't have much of a chance of filling in the gaps. (Hmm now there's a challenge for Jeni, can she provide a stylesheet that will fill in my Mum's birthday...) Anyway for your example, <xsl:for-each select="//*[position()</root/obj]"> <xsl:if test="not(position() = /root/obj)"> <obj><childnode><xsl:value-of select="position()"/></childnode></obj> </xsl:for-each> probably works, but not if node 10 was missing. David _____________________________________________________________________ This message has been checked for all known viruses by Star Internet delivered through the MessageLabs Virus Scanning Service. For further information visit http://www.star.net.uk/stats.asp or alternatively call Star Internet for details on the Virus Scanning Service. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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