Re: [xsl] Parsing a List

[Joerg Heinicke <joerg.heinicke@xxxxxx>]

Hello Kenneth,

you can pass parameters to the stylesheet. In your case for example the 
number of the first element to show in the list:

<xsl:param name="first" select="1"/>
<xsl:param name="count" select="50"/>

> <xsl:template match="DATALIST">
> <table cellpadding="5" cellspacing="0" border="0">
> <tr>
>   <td width="135"><u><font color="green">Company</font></u></td>
>   <td width="330"><u><font color="green">Address </font></u></td>
>   <td width="100"><u><font color="green">Phone </font></u></td>
> <td width="100"></td>
> </tr>
>   <xsl:apply-templates select="customer"/>

changed to:
<xsl:apply-templates select="customer[position() >= $first][position() 
&lt;= $count]"/>

> </table>
> </xsl:template>
> <xsl:template match="customer">
>
> <tr>
> <td valign="top"><a><xsl:attribute name="href">
> adminViewCompanyByID?companyid=<xsl:value-of select="id"/>&#38;companyname
> =<xsl:value-of select="invoicename"/></xsl:attribute><xsl:value-of select="
> invoicename"/></a></td>
> <td valign="top"><xsl:value-of select="invoiceaddress"/></td>
> <td valign="top"><xsl:value-of select="phone"/></td>
> </tr>
> </xsl:template>
>
> Simply, all this code does is displays all customers contained in the
> database. However my problem is that I have 1000s of customers in the
> database and as a result all these are returned in one huge list. My web
> page is therefore ridicously wrong.
>
> Does anyone know anyway of displaying say 50 Customers at a time with a
> 'next' and "previous" link to display  the next or previous 50.
>
> Any help would be greatly appreciated.
>
> Thanks
> - ken

Regards,

Joerg


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