[xsl] XHTML+XSL --> XSL

Hello,

I have created a fairly simple stylesheet that converts XHTML code into an XSL that, when used with any XML document, gives back the original XHTML code.

You may say: This is useless.

And you are absolutely right.

Let's go for an example:

<!-- source1.html -->
<?xml version="1.0" encoding="iso-8859-1"?>
<!DOCTYPE html
    PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
    "DTD/xhtml1-transitional.dtd">
<html>
<head>
<title>Some title with weird entities like&nbsp;&eacute;&icirc;</title>
</head>
<body>
</body>
</html>


When applying my XSL, I get an XSL containing, among other things:
[...]
<xsl:template match="/">
<html>
<head>
<title>Sometitle</title>
</head>
<body>
</body>
</html>
</xsl:template>
[...]


*MY GOAL IS BEING ABLE TO use this source file instead* :
<!-- source2.html -->
<?xml version="1.0" encoding="iso-8859-1"?>
<!DOCTYPE html
    PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
    "DTD/xhtml1-transitional.dtd">
<html>
<head>
<title>Some title with weird entities like&nbsp;&eacute;&icirc;</title>
</head>
<body>
      <xsl:value-of select="/doc/somenode/something" />
      <xsl:apply-templates select="/doc/otherthings" />
</body>
</html>

Well, it does not work, as the xsl:* tags are not recognized as being part of XHTML.

I can act on the HTML file header. The only part that must remain constant is from the <html> tag to the </html> tag.

If I take the <!DOCTYPE ...> out of the document, if I do not have weird entities somewhere in the document, it works nicely. But if I have entities not XML standard, it does not work.

Maybe this is not the rightplace to ask. If so, please tell me so.

Thank you very much.

Antonio Fiol Bonnín

XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list

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