Subject: Re: [xsl] generate-id() question From: Peter Davis <pdavis152@xxxxxxxxx> Date: Mon, 3 Jun 2002 12:37:04 -0700 |
-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 On Monday 03 June 2002 12:04, nrashidi wrote: > Novice question... > I need to create links and i need the output of template match T to > correspond to the ID values that are used in the href. I am not sure what > needs to be put for the node-set argument of generate-id(). > > <xsl:for-each select="SEC"> Here you are effectively calling generate-id(.), where "." is the current <SEC> element. > <a href="#{generate-id()}"> > <xsl:value-of select="."/> > </a> > <xsl:text/> > <xsl:value-of select="following-sibling::*[1]"/><br/> > </xsl:for-each> > </xsl:template> > > <xsl:template match="T"> Now you are calling generate-id() using the current <T> element. > <a name="{generate-id()}"><xsl:value-of select="."/></a><br/> > </xsl:template> All you have to do is look at the relationship between the <T> and the <SEC> and formulate an XPath expression that will get you there. For example, if your input XML looks like this: <T> <SomeElement> <SEC/> </SomeElement> </T> You can do: <xsl:for-each select="SEC"> <a href="#{generate-id(../..)}"> <xsl:value-of select="."/> </a> ... since T is the parent of the parent of the SEC. Unfortunately, without seeing your input XML, I can't really help you more than that. - -- Peter Davis -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.0.6 (GNU/Linux) Comment: For info see http://www.gnupg.org iD8DBQE8+8VgNSZCJx7tYycRAsZhAKC8tlo3+iN8QINflBpUXW5/ia5pKgCZAQZJ uQjM/LRuYbnp5rToZpf0dyw= =FRhx -----END PGP SIGNATURE----- XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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