Re: [xsl] Question using xsl:if and xsl:param

[Oleg Tkachenko <olegt@xxxxxxxxxxxxx>]

There is no == operator in xpath1.0, use ordinary = in a comparison.

Williams, Chris D. wrote:
> I am trying to do a xsl:if with a value that was assigned using xsl:param.
> How do I reference it...here is what I have tried some far using Xalan.
>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
> xmlns:xs="http://www.w3.org/2001/XMLSchema";>
>   <xsl:param name="SHOW_IMAGES"/>
>   <xsl:template match="/">
>   <xsl:if test="$SHOW_IMAGES == 'TRUE'">
>     <!-- Do something -->
>   </xsl:if>
> </xsl>
>
> Here is the error I get.
> (Location of error unknown)XSLT Error
> (javax.xml.transform.TransformerConfigurationException):
> javax.xml.transform.TransformerException: java.lang.RuntimeException:
> Programmer's assertion in getNextStepPos: unknown stepType: -1
>
> any ideas??
> Thanks
> Chris
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list



--
Oleg Tkachenko
Multiconn International, Israel


XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list