[xsl] position() within for-each usage

["Nuri Besen" <nb_news@xxxxxxxxxxx>]

Hello,

I am trying to use the position function to indicate the line I am currently 
processing but I want the position of the parent node.  If the data looks 
like:

<data>
 <item>
   <name>xyz</name>
   <lineitem>
     <cost>24</cost>
   <lineitem>
     <cost>30</cost>
 <item>
   <name>abc</name>
   <lineitem>
     <cost>24</cost>
   <lineitem>
     <cost>30</cost>

and I use a for loop as to output HTML:

<xsl:template match="item">
 <xsl:for-each select="lineitem">
   For item #<xsl:value-of select="position()">
   <xsl:value-of select="../name">
   the cost for lineitem is <xsl:value-of select="cost">
 </xsl:for-each>
</xsl:template>

Here, the output I want should have the item position rather than the 
lineitem position but because of the location it gives me lineitem position, 
which is correct within the loop construct.  So how can I get the parent 
position?
I tried ../self::node()[position()] but no good.

Sample output should be:
For item #1 xyz the cost for lineitem is 24
For item #1 xyz the cost for lineitem is 30
For item #2 abc the cost for lineitem is 24
For item #2 abc the cost for lineitem is 30

BUT it gives:
For item #1 xyz the cost for lineitem is 24
For item #2 xyz the cost for lineitem is 30
For item #1 abc the cost for lineitem is 24
For item #2 abc the cost for lineitem is 24

I know I could have used two templates to match rather than a loop but in 
the real scenario I need to use the loop.

Any help is appreciated....

Thanks,
Nuri

P.S.:  If there is a syntax error, i just typed it in fast, it is the logic 
that i am trying to portray.

_________________________________________________________________
Join the world?s largest e-mail service with MSN Hotmail. 
http://www.hotmail.com


XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list