Subject: Re: [xsl] Variable containing tree From: "Filipe Correia" <filipe.correia@xxxxxxxxxxxxxxx> Date: Fri, 07 Jun 2002 15:03:00 +0100 |
>>> (If you just want to copy the result, then use xsl:copy-of.) >>> >> It works, using xsl:copy-of I get the result I expected. thanks! >> but using <apply-templates> should also work right? I've just realised something... what I really want is xsl:copy-of and not xsl:apply-templates (I guess). When I create the variable I already am applying the templates and I don't want to apply them to the resulting tree a second time; I just want to output the resulting tree. >> I've also tried to use $var/node() but I got the root node in the tree fragment. >> My tree fragmente was something like this: >> >> <node1> >> <node2> >> <node3/> >> <node4/> >> </node2> >> <node5/> >> </node1> >> >> so the result I got when invoquing <xsl:apply-templates >> select="$var/node()" /> was only <node1/> instead of the entire >> tree. This was happening because I had a template processing nodes with the same name has <node1> Now I understand what i was doing wrong. Thanks for your help Filipe XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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