Subject: Re: [xsl] Filtering to the first nodes only From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Wed, 12 Jun 2002 15:47:39 +0100 |
Hi Geoff, > Here is the code that I'm using, per Microsoft's example: > > filterStmt = "Message[position()= 1]"; > firstRow = history[curDim].oDoc.selectNodes(filterStmt); > > Using the "position" statement is supposed to only show the first > level of nodes. My parser rejects the postion() function as not > valid. Probably you haven't set the "SelectionLanguage" property of the DOM Document as "XPath" rather than "XSLPattern" or whatever it is that MSXML uses as the default. The "XSLPattern" language doesn't support as much as XPath and, of course, isn't standard. Assuming that history[curDim].oDoc returns a DOM Document object, use something like: history[curDim].oDoc.setProperty("SelectionLanguage", "XPath"); history[curDim].oDoc.selectNodes("//Message[position() = 1]"); BTW, you can use just [1] instead of [position() = 1] if you like -- it means exactly the same thing. Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] Filtering to the first nodes , Geoffrey V. Brown | Thread | [xsl] question about transforming c, dmitri kerievsky |
RE: [xsl] node() as pattern, DPawson | Date | RE: [xsl] Grouping and Sorting on v, Hunsberger, Peter |
Month |