Subject: [xsl] finding the parent id of an element in an external XML document From: Cindy Mazza <clm6u@xxxxxxxxxxxx> Date: Fri, 14 Jun 2002 09:30:21 -0400 |
Hi, I'm trying to resolve an external cross-reference, but I want to display (by chunking up) the division ancestor element and all its contents. So I know the document, and I know the cross referenced id - I need to find the id of its ancestor that is a div3. (dont' know how clear that was) Here's the XML involved: ----------- (main doc) lz.xml ----------- <xref doc="odes" from="l.09" to="l.10">Book of Odes</xref> ----------- (supporting doc) odes.xml ----------- <TEI.2 id="odes"> .... <div3 id="d3.27"> <head>LIE WEN</head> <lg> <l>...</l> <l id="l.09">What is most distinguished is being virtuous ; --</l> <l id="l.10">It will secure the imitation of all the princes .</l> <l>...</l> </lg> </div3> ... </TEI.2> ----------- I have the following XSLT: <xsl:template match="xref"> <i><a target="new"> <xsl:attribute name="href"> <xsl:text>http://localhost:8080/saxon/servlet/SaxonServlet?source=</xsl:text> <xsl:value-of select="@doc"/>.xml&style=dynaxml.xsl<xsl:text>&chunk.id=</xsl:text> <xsl:choose> <xsl:when test="@from"> <xsl:variable name="dvid">document('../texts/<xsl:value-of select="@doc"/>.xml')//id(@from)/ancestor-or-self::div3[1]/@id</xsl:variable> $dvid </xsl:when> <xsl:otherwise> <!-- ... --> </xsl:otherwise> </xsl:choose> </xsl:attribute> <xsl:apply-templates/> </a></i> </xsl:template> ----------- I can't get the variable dvid to resolve. I know I'm missing something really simple here, but I'm new to XSLT and am having problems figuring it out. Any help would be great. Thanks, ----- - Cindy Cynthia L. Mazza mailto:clm6u@xxxxxxxxxxxx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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