Re: [xsl] is it possible to construct new xml with xsl ?

Subject: Re: [xsl] is it possible to construct new xml with xsl ?
From: Meir <umen@xxxxxxxxxxxxxxxx>
Date: Mon, 17 Jun 2002 11:49:13 -0700
hi
yeah well i know that , but the thing is that im loading xml files not xsl
...
so if i load the xsl its fine ...
but when i load the xml whit the xsl linked its not working ..
i need it to be outputted in as new xml .
tnx
----- Original Message -----
From: "Sebastian Rahtz" <sebastian.rahtz@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Sunday, June 16, 2002 1:20 PM
Subject: Re: [xsl] is it possible to construct new xml with xsl ?


> On Mon, Jun 17, 2002 at 10:46:37AM -0700, Meir wrote:
> >
> > ******************************** THE XSL *******************************
> > <xsl:stylesheet version="1.0"
> > xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
> > <xsl:template match="/">
> >
> > <![CDATA[<?xml version="1.0"?>]]>
> > <![CDATA[<myroot>]]>
>
> just omit all the <![CDATA[ and ]]> from your .xsl file. if you
> say
>  <myroot>
> then
>  <myroot>
> goes into the output.
>
> you are misunderstanding fairly fundamentally how XSLT works.....
> --
> Sebastian Rahtz      OUCS Information Manager
> 13 Banbury Road, Oxford OX2 6NN. Phone +44 1865 283431
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
>



 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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