Re: [xsl] Re: ( Re: [xsl] RE: how I can select the largest attribute value )

Subject: Re: [xsl] Re: ( Re: [xsl] RE: how I can select the largest attribute value )
From: "Vasu Chakkera" <vasucv@xxxxxxxxxxx>
Date: Tue, 18 Jun 2002 15:12:46 +0000
Mike peet has a better solution!!!
cheers mike!


From: "Michael Peet" <mjpeet@xxxxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] Re:
Date: Tue, 18 Jun 2002 10:59:25 -0400

Hi Bodrul,

What you want is:

<xsl:value-of select="/Root/element[not(/Root/element/@length &gt; @length)]/@length"/>

Best Regards,

Mike

From: Bodrul Haque <Bodrul.Haque@xxxxxxxxxxxxxxxxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: "'xsl-list@xxxxxxxxxxxxxxxxxxxxxx'" <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Date: Tue, 18 Jun 2002 15:22:48 +0100

Hi List,

Can someone please tell me how I can select the largest attribute value from
the following xml file, without doing


<xsl:value-of select="Root/element[@length="14"]/@length" />.

(I don't want to use a hard coded value in the predicate). Is there an Xpath
that i can use.
Xml file:
<Root>
<element length="3" />
<element length="14" />
<element length="1" />
<element length="6" />
.....
</Root>


I'm using MSXML3.

Thanks in Advance

Bodrul


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