RE: [xsl] Apply templates + "match all" template

Subject: RE: [xsl] Apply templates + "match all" template
From: "Hunsberger, Peter" <Peter.Hunsberger@xxxxxxxxxx>
Date: Thu, 27 Jun 2002 09:14:28 -0500
You also need a template to do something with the list other than throw it
away.  Add:

  <xsl:template match="list">
	whatever...	
	<xsl:copy-of select="."/>
  </xsl:template>

Then you likely want to change the select to:

      <xsl:apply-templates select="*"/>

since the match will select the nodes you want and it sounds like you'll
eventually want to match other nodes in a generic fashion also...

-----Original Message-----
From: Gustaf Liljegren [mailto:gustaf.liljegren@xxxxxx]
Sent: Thursday, June 27, 2002 9:13 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] Apply templates + "match all" template


Hello all,

I'm making a map from one DTD to another, a pure XSLT task for once. Since
I've not yet dealt with the whole source DTD, I have this template at the
end:

  <xsl:template match="*"/>

The only thing I have done so far are lists and inline content, so in the
root node match I write:

  <xsl:template match="/">
    <doc>
      <xsl:apply-templates select="list"/>
    </doc>
  </xsl:template>

I thought this would make the lists appear and nothing else, but the only
thing I get is:

<?xml version="1.0" encoding="iso-8859-1"?><doc/>

If I remove both the select="list" and <xsl:template match="*"/> I get the
lists, but also all the other content with no markup.

Gustaf


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


Current Thread