Subject: Re: [xsl] XPath iteration? From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 11 Jul 2002 23:48:47 +0100 |
> /Root/SomeNode[position()!=position(/Root/SomeNode)] nodes don't have a position() property, only a position in the current node list, so teh same node will have different positions depending on how it is accessed (eg it always has position()=1 if accessed by .. ) so position(/Root/SomeNode) is a syntax error, I can't actually guess what you wanted your entire expression to mean, but usually when people try position(...) they want something like 1+count(/root/SomeNode/preceding-sibling::*) David _____________________________________________________________________ This message has been checked for all known viruses by Star Internet delivered through the MessageLabs Virus Scanning Service. For further information visit http://www.star.net.uk/stats.asp or alternatively call Star Internet for details on the Virus Scanning Service. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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