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Subject: RE: [xsl] grouping consecutive elements From: "Michael Kay" <michael.h.kay@xxxxxxxxxxxx> Date: Fri, 12 Jul 2002 18:20:40 +0100 |
>
> trying to transform an XML document obtained by using MajiX
> we don´t know how to group consecutive XML elements into a
> single one. For example we want to group consecutive <b>
> siblings into a single <b> or consecutive <i> into a single
> <i>, keeping always their internal structure.
>
It's not actually an easy problem. The following kind of technique is
sometimes useful:
<xsl:template match="b">
<b>
<xsl:copy-of select="."/>
<xsl:apply-templates
select="following-sibling::*[1][self::b]"
mode="more"/>
</b>
<xsl:apply-templates
select="following-sibling::[not(self::b)][1]"/>
</xsl:template>
<xsl:template match="b" mode="more">
<xsl:copy-of select="."/>
<xsl:apply-templates
select="following-sibling::*[1][self::b]"
mode="more"/>
</xsl:template>
and similarly for the other elements that occur. It's basically applying
templates "horizontally" rather than "vertically", a special case of
recursive processing rather than iterative processing.
Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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