|
Subject: RE: [xsl] Grouping on multiple nested elements From: Jarno.Elovirta@xxxxxxxxx Date: Tue, 16 Jul 2002 11:06:23 +0300 |
Hi,
> I have no problem grouping by program_name using the
> Muenchian method -
> there is only one program_name for each story. However,
> grouping by subject
> has me stumped - do I need multiple keys and how do I keep
> track of the
> current subject?
Did you mean
<xsl:key name="story" match="story" use="subjects/subject" />
<xsl:key name="subject" match="subject" use="." />
<xsl:template match="data">
<xsl:for-each select="story/subjects/subject[generate-id() = generate-id(key('subject', .))]">
<xsl:sort select="." />
<xsl:value-of select="." />
<xsl:text>

</xsl:text>
<xsl:for-each select="key('story', .)">
<xsl:text> </xsl:text>
<xsl:value-of select="story_title" />
<xsl:text>
 </xsl:text>
<xsl:value-of select="description" />
<xsl:text>

</xsl:text>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
"Launch auto-documentation daemon" and all that,
Santtu
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
| Current Thread |
|---|
|
| <- Previous | Index | Next -> |
|---|---|---|
| Re: [xsl] Grouping on multiple nest, Jeni Tennison | Thread | [xsl] RE: XSL FAQ Page - encoding i, DPawson |
| Re: [xsl] Re: WML input problem, Joerg Heinicke | Date | RE: [xsl] Matching node by its posi, Michael Kay |
| Month |