Subject: [xsl] String manipulation question From: Bodrul Haque <Bodrul.Haque@xxxxxxxxxxxxxxxxxxxxxxx> Date: Fri, 19 Jul 2002 13:16:26 +0100 |
Hi Everyone, My question is regarding some string manipulation. I have template which looks at a string value of a date (eg 02-03-02 param1) and a dateformat (eg. DD-MM-YY param2). My template has to (for e.g.): return 02-03-02 if param1= 2-3-02 and param2= DD-MM-YY or return 02/03/2002 if param1= 02/3/02 and param2= DD-MM-YYYY I'm having difficulties in thinking of a short and neat way of appending '0' in front of any number between 1-9 (if its not already there). [And appending a '20' for a year format (if its not already there)]. Any help appreciated. Template -------- <xsl:template name="dateFormat"> <xsl:param name="str"> <xsl:param name="date-format"> <xsl:variable name="str2"> <xsl:choose> <xsl:when test="string-length($str) = string-length($date-format)"> <xsl:value-of select="$str"/> </xsl:when> <xsl:otherwise> <!-- need some help here --> </xsl:otherwise> </xsl:choose> </xsl:variable> </xsl:template> Regards Bodrul --------------------------------------------------------------------------- The information transmitted is intended only for the person or entity to which it is addressed and may contain confidential and/or privileged material. Any views or opinions presented in this Email message are solely those of the author and do not necessarily represent those of Synergy Logistics Limited unless specifically stated. Email communications are not necessarily secure and therefore Synergy Logistics Limited does not accept legal responsibility for the contents of this message. If you are not the intended recipient and have received this message in error, Please notify Synergy Logistics Limited immediately. Synergy Logistics Ltd. 01509 232706 XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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