Subject: RE: [xsl] transformation does happen after copy-of? From: Américo Albuquerque <aalbuquerque@xxxxxxxxxxxxxxxx> Date: Tue, 23 Jul 2002 11:53:41 +0100 |
So why does the values of the attributes get print out?? -----Original Message----- From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of David Carlisle Sent: Tuesday, July 23, 2002 11:25 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] transformation does happen after copy-of? > I supose that the attribute nodes does't get selected in the node() > function node() isn't a function, it is a node test, like text(). attribute nodes are matched by node() but select="node()" is short for select="child::node()" and attribute nodes are not child nodes of any node. > so, when you do a match="node()" you are selecting all nodes except > attribute nodes, b no node() does match attribute nodes. > but these also have text nodes (that contain > there values) and these are selected by the match="node()" attribute nodes do not have any children. The value of an attribute i not a text node. david _____________________________________________________________________ This message has been checked for all known viruses by Star Internet delivered through the MessageLabs Virus Scanning Service. For further information visit http://www.star.net.uk/stats.asp or alternatively call Star Internet for details on the Virus Scanning Service. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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