Subject: [xsl] merge tree structure with no redundancy From: Benoit Guyon <ben@xxxxxxxxxx> Date: Fri, 2 Aug 2002 17:42:50 +0200 |
hello, I have a XML file with nodes that are representing a tree structure. i want to modify this file (with a XSL stylesheet) to get a new XML file with a unified tree structure that don't have redundancy. the original file : <?xml version="1.0" encoding="ISO-8859-1"?> <a> <subscribers> <subscriber> <id="1" /> <path> <node type="T1" name="N1"> <node type="T2" name="N2"> <node type="T3" name="N3" /> </node> </node> </path> </subscriber> <subscriber> <id="2" /> <path> <node type="T1" name="N1"> <node type="T2" name="N2"> <node type="T3" name="N4" /> </node> </node> </path> </subscriber> </subscribers> </a> the wanted file : <?xml version="1.0" encoding="ISO-8859-1"?> <a> <node type="T1" name="N1"> <node type="T2" name="N2"> <node type="T3" name="N3" id="1" /> <node type="T3" name="N4" id="2" /> </node> </node> </a> I don't know how to make that ... can i test output to detect if a node (identified with type and name atributes) is already present ? when i'm in the second <subscriber> node, how can i detect that i already wrote the ancestor nodes, and how can i write the final node under the right ancestor ? does anybody have an idea or a general algorithm to help me ? best regards ben PS : i use MSXML, i don't have the saxon:path() :/ ;) XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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